In: Statistics and Probability
In a random sample of 5 residents of the state of Texas, the mean waste recycled per person per day was 1.9 pounds with a standard deviation of 0.89 pounds. Determine the 99% confidence interval for the mean waste recycled per person per day for the population of Texas. Assume the population is approximately normal. Step 1 of 2 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places. Step 2 of 2 : Construct the 99% confidence interval. Round your answer to one decimal place.
solution
Given that,
= 1.9
s =0.89
n = 5
Degrees of freedom = df = n - 1 = 5- 1 = 4
At 99% confidence level the t is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
t
/2 df = t0.005, 4=
4.602 ( using student t
table)
Margin of error = E = t/2,df
* (s /
n)
= 4.602 * (0.89 /
5) = 1.832
The 99% confidence interval estimate of the population mean is,
- E <
<
+ E
1.9 - 1.832<
< 1.9 + 1.832
0.068 <
< 3.732
(0.07 , 3.7)