In: Statistics and Probability
Suppose the sales team at Apple is interested in investigating
whether the colours of the iPod Touch have any impact on sales. To
test this, they use five different colours for the new iPod Touch.
The following table shows the number of each colour of 1335 iPods
sold during the first month at one retailer. At the 1% significance
level, test whether the number of iPods sold in each colour is
uniform. Keep 4 decimal places for intermediate calculations.
iPod colour |
iPods sold |
Grey |
290 |
White |
235 |
Pink |
290 |
Lime |
280 |
Teal |
240 |
Please provide correct answers without using excel formulas. thanks.
As we are testing here whether number of iPods sold in each colour is uniform, therefore the expected number of ipods sold for each colour here is computed as:
= Total ipods sold / 5
= 1335/5
= 267
Using the above expected value, the chi square test statistic here is computed as:
The computations are made in the following table here:
Ipod Colour | Ipods Sold(O_i) | E_i | (O_i - E_i)^2/E_i |
Grey | 290 | 267 | 1.981 |
White | 235 | 267 | 3.835 |
Pink | 290 | 267 | 1.981 |
Lime | 280 | 267 | 0.633 |
Teal | 240 | 267 | 2.730 |
1335 | 1335 | 11.161 |
Therefore 11.161 is the required chi square test statistic value here.
For n - 1 = 4 degrees of freedom, we get the p-value from the chi square distribution tables here as:
As the p-value here is 0.02 > 0.01 which is the level of significance, therefore the test is not significant here and we cannot reject the null hypothesis here. Therefore we don't have sufficient evidence that the distribution of the 5 colours is not uniform here.