In: Statistics and Probability
A car dealership claims that its average service time is less than 7 hours on weekdays. A random sample of 16 service times was recorded and yielded the statistics x ̅=6.75 hours and s= 1.62 hours. Assume service times are normally distributed, is there enough evidence to support the dealership’s claim at 5% significance level? 10 marks (Please show every step for full marks)
Hypotheses:
Rejection Region:
Test Statistic:
Decision/Conclusion:
This is the left tailed test .
The null and alternative hypothesis is
H0 : = 7
Ha : < 7
Test statistic = t
= ( - ) / s / n
= (6.75 - 7) / 1.62 / 16
= -0.617
Test statistic = -0.617
df = 15
P-value = 0.2732
= 0.05
P-value >
Fail to reject the null hypothesis .
There is insufficient evidence to support the dealership’s claim at 5% significance level .