In: Statistics and Probability
The owner of a new car dealership claims the average number of days it takes his dealership to sell a Chevrolet Aveo is 50 days. A random sample of 50 cars had a mean time on the dealer’s lot of 64 days. Assume the population standard deviation to be 7.0 days. Find the 95% confidence interval estimate of the population mean. State the Margin of Error, Best Point Estimate and Include the written statement
Please list all the work.
Solution :
Given that,
Point estimate = sample mean = = 64
Population standard deviation = = 7.0
Sample size n =50
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table )
Margin of error = E = Z/2
* (
/n)
= 1.96* ( 7.0/ 50 )
= 1.9403
At 95% confidence interval estimate of the population mean
is,
- E < < + E
64 - 1.9403 <
< 64 + 1.9403
62.0597 <
< 65.9403
( 62.0597 , 65.9403 )
Point estimate = sample mean = = 64