In: Statistics and Probability
Consider the observations taken on the continuous random
variable Y given below.
Graph the data using...
Consider the observations taken on the continuous random
variable Y given below.
- Graph the data using an appropriate plot. Comment on the key
features of the graph.
- Assess the normality of the data set. What do you
conclude?
- Compute the 5-number summary.
- Treat the sample mean and sample standard deviation as if they
are the true population mean and standard deviation. Find P (Y >
90).
- Treat the sample mean and sample standard deviation as if they
are the true population mean and standard deviation. With a sample
size of n = 50, what is the sampling distribution of the sample
average?
- For a sample of size n = 50, find P(Y >
88.73).
x/y
|
0
|
1
|
P(X=x)
|
0
|
0.72
|
0.08
|
0.80
|
1
|
0.08
|
0.12
|
0.20
|
P(Y=y)
|
0.80
|
0.20
|
1
|
marginal probability
=
0.20, x=1
=
0.20, y=1
P (Y=1 | X = 1) = P(Y=1, X=1)/P(X=1)
=
0.12/0/20
= 0.6
P (Y=1| X = 0)= P(Y-1, X=0)/P(X=0)
= 0.08/0.80
= 0.1
P (X = 1 ∪ Y = 1) = P(X=1) + P(Y=1) – P(X=1, Y=1)
= 0.20 + 0.2 – 0.12
= 0.28
E(X) = , P(X=x) = 0.20
- E(Y) = , P(y=y) = 0.20
- E() = , P(X=x) = 0.20, E() = 0.20
Var(x) = E() - (x) = 0.16,
var(y)=var(x) = 0.16
- Cov(x,y) = E(xy) – Ex)(Ey)
- E(xy) = P(X=x) P(Y=y) = 0.12
- Cov(x,y) = 0.12 – = 0.08