please give a sequence in the form an= that is monotonic, bounded and convergent.

please give a sequence in the form an=

that is monotonic, bounded and convergent.

Expert Solution

feel free to ask any doubt please. If you don't have any doubt please like.

milcah answered 1 year ago

Show that every cauchy sequence of reals is convergent

Can a conditionally convergent series be rearranged to form an absolutely convergent series ?

1. prove that if{xn} is decreasing an bounded from below, then {xn} is convergent.

Let sequence an be a bounded sequence and let E be the set of subsequential limits...

Let sequence an be a bounded sequence and let E be the set of subsequential limits of an. prove that E is bounded and contains both sup E and inf E

Show that a monotone sequence converges if and only if it is bounded.

Define convergent evolution and give an example. Why is convergent evolution often tricky for phylogenies?

Please solve fully Determine whether the geometric series is convergent or divergent. If it is convergent,...

Please solve fully Determine whether the geometric series is convergent or divergent. If it is convergent, find its sum.8 − 11 + 121 8 − 1331 64 + Step 1 To see 8 − 11 + 121 8 − 1331 64 + as a geometric series, we must express it as ∞ ar n − 1 n = 1 . For any two successive terms in the geometric series ∞ ar n − 1 n = 1 , the ratio of...

Prove that if a sequence is bounded, then limsup sn is a real number.

Let {an} be a bounded sequence. In this question, you will prove that there exists a...

Let {an} be a bounded sequence. In this question, you will prove that there exists a convergent subsequence. Define a crest of the sequence to be a term am that is greater than all subsequent terms. That is, am > an for all n > m (a) Suppose {an} has infinitely many crests. Prove that the crests form a convergent subsequence. (b) Suppose {an} has only finitely many crests. Let an1 be a term with no subsequent crests. Construct a...

Let (an) be a real sequence in the standard metric. Prove that (an) is bounded if...

Let (an) be a real sequence in the standard metric. Prove that (an) is bounded if and only if every subsequence of (an) has a convergent subsequence.

Question