E.C. 2. (10 pts.) Suppose that (sn) is a sequence of real
numbers such that sn ≥ 0 for all n ∈ N. (a) Show that the set of
subsequential limits of S satisfies S ⊆ [0,∞) ∪ {+∞}. (b) Is it
possible for S = [0,∞) ? (Hint: apply Theorem 11.9.)
Legible handwriting is a must
Sn = (1+(1/n))^n
(a) Prove Sn is strictly increasing (b) bounded below by 2 and
above by 3
(c) Sn converges to e
(d) Obtain an expression for e
(e) Prove e is irrational
Let {an} be a bounded sequence. In this question,
you will prove that there exists a convergent subsequence.
Define a crest of the sequence to be a
term am that is greater than all subsequent terms. That is,
am > an for all n > m
(a) Suppose {an} has infinitely many crests. Prove
that the crests form a convergent subsequence.
(b) Suppose {an} has only finitely many crests. Let
an1 be a term with no subsequent crests. Construct a...
Let A be a subset of all Real Numbers. Prove that A is closed
and bounded (I.e. compact) if and only if every sequence of numbers
from A has a subsequence that converges to a point in A.
Given it is an if and only if I know we need to do a forward and
backwards proof. For the backwards proof I was thinking of
approaching it via contrapositive, but I am having a hard time
writing the proof in...
Let (sn) be a sequence that converges.
(a) Show that if sn ≥ a for all but finitely many n,
then lim sn ≥ a.
(b) Show that if sn ≤ b for all but finitely many n,
then lim sn ≤ b.
(c) Conclude that if all but finitely many sn belong to [a,b],
then lim sn belongs to [a, b].
Prove Corollary 4.22: A set of real numbers E is closed and
bounded if and only if every infinite subset of E has a point of
accumulation that belongs to E.
Use Theorem 4.21: [Bolzano-Weierstrass Property] A set of real
numbers is closed and bounded if and only if every sequence of
points chosen from the set has a subsequence that converges to a
point that belongs to E.
Must use Theorem 4.21 to prove Corollary 4.22 and there should...