In: Statistics and Probability
A sample of 40 observations is selected from a normal population. The sample mean is 31, and the population standard deviation is 3. Conduct the following test of hypothesis using the 0.05 significance level.
H0: μ ≤ 30
H1: μ > 30
"One-tailed"—the alternate hypothesis is greater than direction.
"Two-tailed"—the alternate hypothesis is different from direction.
Do not reject
Reject
Solution :
= 30
=31
=3
n = 40
This is the right tailed test .
The null and alternative hypothesis is ,
H0 : < 30
Ha : >30
Test statistic = z
= ( - ) / / n
= 31(-30) / 3 / 40
= 2.11
Test statistic = z = 2.11
The critical value = 1.645
Test statistic > The critical value
P(z > 2.11 ) = 1 - P(z < 2.11 ) = 0.9826
P-value =0.0174
= 0.05
P-value <
0.0174 <0.05
Reject the null hypothesis .
There is sufficient evidence to suggest that