Question

Table 1 below provides slopes, standard errors, and beta’s for several variables used to predict levels of self-control (higher scores = lower self-control) for respondents living in “good” and “bad” neighborhoods.

Table 1. OLS Regression Predicting Low Self-Control Across Neighborhood Type
	Good Neighborhoods (n = 356)			Bad Neighborhoods (n = 186)
Measure	B	SE	Beta	B	SE	Beta
Age (in Years)	-.215*	.094	-.117	.107	.160	.050
Sex (1 = Males)	.699**	.224	.160	.129	.361	.026
Race (1 = Whites)	.059	.261	.012	-.499	.382	-.101
Parental Supervision (Higher = More Supervision)	-.277**	.023	-.063	-.026	.364	-.005
Parental Responsiveness (Higher = More Responsive)	-.098**	.032	.161	.096	.058	.228
School Socialization (Higher = More Socialization)	-.249**	.085	-.154	-.042	.112	-.027
Maternal Smoking (1 = Smoked During Pregnancy)	.580*	.277	.109	1.02**	.388	.193
Constant	6.105	1.750		.460	2.620
R2	.313			.273

* p < .05; ** p < .01

4.          A coefficient is significant when the t value associated with the coefficient exceeds the     critical t value at the appropriate degrees of freedom. In table 1, calculate the t value for     school socialization and maternal smoking variables (2 separate t values).

Answer 1

School Socialization:

For Good

estimated slope=   -0.249                  
std error =    0.085                  
                      
t-test statistic =    t = estimated slope / std error =   -0.249   /   0.085   =   -2.929

For Bad:

estimated slope=   -0.042                  
std error =    0.112                  
                      
t-test statistic =    t = estimated slope / std error =   -0.042   /   0.112   =   -0.375

---------------

maternal smoking variables

For Good:

estimated slope=   0.58                  
std error =    0.277                  
                      
t-test statistic =    t = estimated slope / std error =   0.58   /   0.277   =   2.094

For Bad:

estimated slope=   1.02                  
std error =    0.388                  
                      
t-test statistic =    t = estimated slope / std error =   1.02   /   0.388   =   2.629

Thanks in advance!

revert back for doubt

Please upvote