In: Statistics and Probability
The method of tree ring dating gave the following years A.D. for an archaeological excavation site. Assume that the population of x values has an approximately normal distribution.
1285 | 1194 | 1313 | 1264 | 1268 | 1316 | 1275 | 1317 | 1275 |
(a) Use a calculator with mean and standard deviation keys to find the sample mean year x and sample standard deviation s. (Round your answers to the nearest whole number.)
x = | A.D. |
s = | yr |
(b) Find a 90% confidence interval for the mean of all tree ring
dates from this archaeological site. (Round your answers to the
nearest whole number.)
lower limit | A.D. |
upper limit | A.D. |
Solution :
We are given a data of sample size n = 9
1285,1194,1313,1264,1268,1316,1275,1317,1275
Using this, first we find sample mean() and sample standard deviation(s).
=
= (1285 + 1194.......+ 1275)/9
= 1279 A.D.
Now ,
s=
Using given data, find Xi - for each term.Take square for each.Then we can easily find s.
s = 39 yr
Note that, Population standard deviation() is unknown..So we use t distribution.
Our aim is to construct 90% confidence interval.
c = 0.90
= 1 - c = 1 - 0.90 = 0.10
/2 = 0.10 2 = 0.05
Also, d.f = n - 1 = 8
= = 0.05,8 = 1.86
( use t table or t calculator to find this value..)
The margin of error is given by
E = /2,d.f. * ( / n )
= 1.86* ( 39/ 9 )
= 24.17
Now , confidence interval for mean() is given by:
( - E ) < < ( + E)
( 1279 - 24.17 ) < < ( 1279 + 24.17 )
1255 < < 1304
Required 90% confidence interval is ( 1255 , 1304 )
Lower limit = 1255 A.D.
Upper limit = 1304 A.D.