Question

In: Statistics and Probability

A traffic cop has been determined that (2%) of drivers checked use their mobile phones and...

A traffic cop has been determined that (2%) of drivers checked use their mobile phones and (8%) of drivers checked do not wear seat belts. In addition, it has been observed that the two infractions are independent of one another. If the cop stops seven drivers at random:

a. Calculate the probability that exactly five of the drivers have committed any one of the two offenses.

b. Calculate the probability that at least one of the drivers checked has committed at least one of the two offenses.

Solutions

Expert Solution

Answer:

a)

P(any one of the two offenses) = 0.02 + 0.08 = 0.10

{Since they are independent}

Let X denote the number of people out of the people checked who committed any one of the two offenses.

Then

Required probability =

b)

P(at least one of the two offenses) = 1 - P(none of the two offences)

= 1 - (1-0.02)(1-0.08) = 0.0984

{Since they are independent}

Let X denote the number of people out of the people checked who committed at least one of the two offenses.

Then,

Required probability =

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