Question

In: Chemistry

1. A student carries out an esterification reaction where he used 1.5 mL of butyric acid...

1. A student carries out an esterification reaction where he used 1.5 mL of butyric acid and 1.0 mL of methanol. Obtained 1.0 mL of product. Calculate the theoretical yield and% yield (from grams of product).

2. What are the reaction conditions that favor the SN2 mechanism in the
laboratory?

3. What are the reaction conditions that favor the SN1 mechanism in the
laboratory?

4. What property do low molecular weight esters have?

PLEASE ANSWER ALL THE QUESTIONS AND DON'T WRITE THE ANSWERS ON A PAPER. THANKS!

Solutions

Expert Solution

Ans:

1 Butyric acid + 1 Methanol ---> 1 methyl butyrate

Butyric acid and methanol react in 1:1 ratio to form 1 mol of ester

Molecular mass, M

Volume taken, V

Density,d = mass/V

Mass, w = d x V

Mole, n

= w/M

Butyric acid

C4H8O2

88.11 g/mol

1.5 mL

0.9528 g/mL

1.4292 g

0.0162

Limiting reagent

Methanol

CH3OH

32.04 g/mol

1.0 mL

0.792 g/mL

0.792 g

0.0247

Methyl butyrate

C5H10O2

102.13 g/mol

1.0 mL

(obtained)

0.898 g/mL

0.898 g

(yield obtained)

0.0088

(obtained)

Here Butyric acid is the limiting reagent.

In a reaction limiting reagent is completely consumed. So, 0.0162 mol of butyric acid is expected to give 0.0162 mol of methyl butyrate.

Yield expected (theoretical yield) = 0.0162 x 102.13 = 1.6545 g

% yield = yield obtained/theoretical yield = (0.898/1.6545)x100= 54.28 %

Ans 2 & 3:

Conditions favoring SN1

Conditions favoring SN2

Tertiary alkyl halides are better reactants

Primary alkyl halides are better reactants

A weak nucleophile (neutral nucleophile) is a better choice

A strong nucleophile (negatively charged nucleophile) is a better choice

Polar protic solvents like H2O, alcohol helps

Polar aprotic solvents like DMF, DMSO helps

Higher concentration of alkyl halide increases the rate

Higher concentration of alkyl halide & nucleophile increases the rate

Ans 4:

Low molecular weight esters:

  • Have pleasant smell, so are used in fragrances and essential oils.
  • They are more flexible and have low polarity (in comparison to amides of comparable mass).
  • Have lower melting point and more volatile (in comparison to amides of comparable mass)
  • Are slightly soluble in water because of their capacity to form H-bonding.

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