In: Chemistry
Ans:

1 Butyric acid + 1 Methanol ---> 1 methyl butyrate
Butyric acid and methanol react in 1:1 ratio to form 1 mol of ester
| 
 Molecular mass, M  | 
 Volume taken, V  | 
 Density,d = mass/V  | 
 Mass, w = d x V  | 
 Mole, n = w/M  | 
|
| 
 Butyric acid C4H8O2  | 
 88.11 g/mol  | 
 1.5 mL  | 
 0.9528 g/mL  | 
 1.4292 g  | 
 0.0162 Limiting reagent  | 
| 
 Methanol CH3OH  | 
 32.04 g/mol  | 
 1.0 mL  | 
 0.792 g/mL  | 
 0.792 g  | 
 0.0247  | 
| 
 Methyl butyrate C5H10O2  | 
 102.13 g/mol  | 
 1.0 mL (obtained)  | 
 0.898 g/mL  | 
 0.898 g (yield obtained)  | 
 0.0088 (obtained)  | 
Here Butyric acid is the limiting reagent.
In a reaction limiting reagent is completely consumed. So, 0.0162 mol of butyric acid is expected to give 0.0162 mol of methyl butyrate.
Yield expected (theoretical yield) = 0.0162 x 102.13 = 1.6545 g
% yield = yield obtained/theoretical yield = (0.898/1.6545)x100= 54.28 %
Ans 2 & 3:
| 
 Conditions favoring SN1  | 
 Conditions favoring SN2  | 
| 
 Tertiary alkyl halides are better reactants  | 
 Primary alkyl halides are better reactants  | 
| 
 A weak nucleophile (neutral nucleophile) is a better choice  | 
 A strong nucleophile (negatively charged nucleophile) is a better choice  | 
| 
 Polar protic solvents like H2O, alcohol helps  | 
 Polar aprotic solvents like DMF, DMSO helps  | 
| 
 Higher concentration of alkyl halide increases the rate  | 
 Higher concentration of alkyl halide & nucleophile increases the rate  | 
Ans 4:
Low molecular weight esters: