In: Chemistry
Ans:
1 Butyric acid + 1 Methanol ---> 1 methyl butyrate
Butyric acid and methanol react in 1:1 ratio to form 1 mol of ester
Molecular mass, M |
Volume taken, V |
Density,d = mass/V |
Mass, w = d x V |
Mole, n = w/M |
|
Butyric acid C4H8O2 |
88.11 g/mol |
1.5 mL |
0.9528 g/mL |
1.4292 g |
0.0162 Limiting reagent |
Methanol CH3OH |
32.04 g/mol |
1.0 mL |
0.792 g/mL |
0.792 g |
0.0247 |
Methyl butyrate C5H10O2 |
102.13 g/mol |
1.0 mL (obtained) |
0.898 g/mL |
0.898 g (yield obtained) |
0.0088 (obtained) |
Here Butyric acid is the limiting reagent.
In a reaction limiting reagent is completely consumed. So, 0.0162 mol of butyric acid is expected to give 0.0162 mol of methyl butyrate.
Yield expected (theoretical yield) = 0.0162 x 102.13 = 1.6545 g
% yield = yield obtained/theoretical yield = (0.898/1.6545)x100= 54.28 %
Ans 2 & 3:
Conditions favoring SN1 |
Conditions favoring SN2 |
Tertiary alkyl halides are better reactants |
Primary alkyl halides are better reactants |
A weak nucleophile (neutral nucleophile) is a better choice |
A strong nucleophile (negatively charged nucleophile) is a better choice |
Polar protic solvents like H2O, alcohol helps |
Polar aprotic solvents like DMF, DMSO helps |
Higher concentration of alkyl halide increases the rate |
Higher concentration of alkyl halide & nucleophile increases the rate |
Ans 4:
Low molecular weight esters: