Titration of acid with base is an exothermic reaction. Neutralization of 15 mL of H3PO4 acid...

Titration of acid with base is an exothermic reaction. Neutralization of 15 mL of H3PO4 acid with 8 mL potassium hydroxide released 780 J heat. Find molarity of the acid and the base?

H3PO4 (aq) + 3 KOH (aq) = K3PO4 (aq) + 3 H2O (l)

Delta H X rxn = -124.8 kJ

Expert Solution

1 mol fo H3PO4 gives 124.8 KJ = 124800 J
Total heat released = 780 J
Number of moles of H3PO4= 780/124800 = 6.25*10^-3 mol
Molarity of H3PO4 = number of moles/ volume
= (6.25*10^-3 mol) / (0.015 L)
= 0.41 M

3 mol of KOH gives 124.8 KJ = 124800 J
Total heat released = 780 J
Number of moles of KOH= 3*780/124800 = 0.01875 mol
Molarity of KOH= number of moles/ volume
= (0.01875 mol) / (0.008 L)
= 2.344 M

queen_honey_blossom answered 3 months ago

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