In: Statistics and Probability
Using the Instructor ranking data conduct a simple linear regression to predict a student’s scores based on the number of hours the student studies and answer the following questions:
Class Participation | Actual grade | Hours Studying | gender |
1 | 98 | 5 | f |
2 | 94 | 5 | f |
3 | 88 | 4 | m |
4 | 91 | 4.5 | f |
5 | 93 | 4.1 | m |
6 | 88 | 3.8 | f |
7 | 88 | 3 | f |
8 | 85 | 3 | m |
9 | 82 | 3 | m |
10 | 66 | 2 | m |
11 | 71 | 1 | f |
12 | 61 | 1 | m |
using minitab>stat>regression
we have
Regression Analysis: Score versus Hours Studying
Analysis of Variance
Source DF Adj SS Adj MS F-Value P-Value
Regression 1 1310.78 1310.78 69.18 0.000
Error 10 189.47 18.95
Total 11 1500.25
Model Summary
S R-sq R-sq(adj) R-sq(pred)
4.35277 87.37% 86.11% 80.09%
Coefficients
Term Coef SE Coef T-Value P-Value VIF
Constant 57.89 3.35 17.27 0.000
Hours Studying 7.875 0.947 8.32 0.000 1.00
Regression Equation
Score = 57.89 + 7.875 Hours Studying
Ans 1 the value of the intercept of this regression equation is 57.89
Ans 2 ) the value of the slope of this regression equation is 7.875
interpretation : for every one hour increase in the study hours the value of grade/score in exam increase by 7.875
Ans 3 ) the regression model
Score = 57.89 + 7.875 Hours Studying
Ans 4 ) R2 = 0.8737 , it means that about 87.37 % variation in score can be explained by number of hour studying
ANs 5 ) F = 69.18 , F (F ratio) is = MS(regression) /MS(Error) = 1310.78/18.95 = 69.18
it means that model is significant tou use because F value is large than F critical value