Question
In: Statistics and Probability
In a recent survey of county high school students, 100 males and 100 females, 66 of...
In a recent survey of county high school students, 100 males and 100 females, 66 of the male students and 47 of the female students sampled admitted that they consumed alcohol on a regular basis. Find a 90% confidence interval for the difference between the proportion of male and female students that consume alcohol on a regular basis. Can you draw any conclusions from the confidence interval?
For the test of significance questions, clearly indicate each of the formal steps in the test of significance.
Step 1: State the null and alternative hypothesis.
Step 2: Calculate the test statistic.
Step 3: Find the p-value.
Step 4: State your conclusion. (Do not just say “Reject H0” or “Do
not reject H0”, state the conclusion in the context of the
problem.)
Solutions
orchestra answered 2 years agoRelated Solutions
A recent study of high school students shows the percentage of females and males who have...
A recent study of high school students shows the percentage of
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school students was interviewed. The students were asked whether
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record. Of the 100 females, 21 answered yes, as did 145 of the 400
males.
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Answer
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Question 1 A recent national survey found that high school students watched an average of 6.8...
Question 1
A recent national survey found that high school students watched
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school students revealed that the mean number of vidoes watched
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A recent national survey found that high school students watched an average (mean) of 6.6 DVDs...
A recent national survey found that high school students watched
an average (mean) of 6.6 DVDs per month with a population standard
deviation of 0.90 hour. The distribution of DVDs watched per month
follows the normal distribution. A random sample of 43 college
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A recent national survey found that high school students watched an average (mean) of 6.6 DVDs...
A recent national survey found that high school students watched
an average (mean) of 6.6 DVDs per month with a population standard
deviation of 0.90 hour. The distribution of DVDs watched per month
follows the normal distribution. A random sample of 43 college
students revealed that the mean number of DVDs watched last month
was 6.10. At the 0.05 significance level, can we conclude that
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