In: Statistics and Probability
Ho: μ ≤ 51
H1: μ > 51
A sample of 60 is used and the population standard deviation is 8. Use α=0.05.
Solution:
We are given the following hypothesis test:
Ho: μ ≤ 51
H1: μ > 51
Sample size = n = 60
Population standard deviation =
Level of significance = α = 0.05.
Part a) Z critical =..........?
Since H1: μ > 51 is > type, this is right tailed test.
Thus find an area = 1 - α = 1 - 0.05 = 0.95
Look in z table for Area = 0.9500 or its closest area and find corresponding z value.
Area 0.9500 is in between 0.9495 and 0.9505 and both the area are at same distance from 0.9500
Thus we look for both area and find both z values
Thus Area 0.9495 corresponds to 1.64 and 0.9505 corresponds to 1.65
Thus average of both z values is : ( 1.64+1.65) / 2 = 1.645
Thus Zcritical = 1.645
Z critical = 1.645
Part b) Sample mean = 53.5, z calc = ____________?
.
Since > Z critical = 1.645, we reject H0.
Part c) Sample mean = 51.8, z calc = ______?
.
Since < Z critical = 1.645, we do not reject H0.
Part d) The P-value for c is:......?
For right tailed test , P-value is:
P-value = P(Z > z test statistic)
P-value = P(Z > 0.77)
P-value =1 - P(Z < 0.77)
Look in z table for z = 0.7 and 0.07 and find corresponding area.
P( Z < 0.77 ) = 0.7794
thus
P-value =1 - P(Z < 0.77)
P-value =1 -0.7794
P-value =0.2206