draw the unit cell of a lead sulfide , in which there are sulfide anions in...

draw the unit cell of a lead sulfide , in which there are sulfide anions in a face centered cubic lattice , and lead cations are in alternate tetrahedral holes. Derive the stoichiometry of the mineral and the charge of the lead cation.

Solutions

Expert Solution

In FCC, there is 1 aton at each of the 8 corners of the unit cell shared by 8 surrounding unit cells and 1 atom at each of the 6 faces shared by 2 surrounding unit cells.

Hence number of sulfide (S^2-) anions per unit cell = 8 x (1/8) + 6 x (1/2) = 4 S^2- anions.

In FCC there are a total of 8 tetrahedral holes per unit cell.

Since lead cations occupy alternate tetrahedral holes, number of lead cations per unit cell = 8/2 = 4 Pb cation.

Since there are equal number of cations and anions, the charge on both the cations and anions are same.

Hence charge of lead cation = +2 (answer)

Stoichiometry of the mineral = Pb4S4 or PbS (answer)

For structure take a 3d figure for the structure of PbS from internet.

queen_honey_blossom answered 2 years ago

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