Question

In: Chemistry

17. A. The molar solubility of lead sulfide in a 0.219 M lead nitrate solution is...

17. A. The molar solubility of lead sulfide in a 0.219 M lead nitrate solution is _____M.

B. The maximum amount of calcium carbonate that will dissolve in a 0.195M potassium carbonate solution is _____M.

C. The molar solubility of barium carbonate in a 0.132 M potassium carbonate solution is _____M.

Solutions

Expert Solution

Q17. A.) molar solubility of lead sulfide = 4.06 x 10-28 M

B.) maximum amount of calcium carbonate = 1.72 x 10-8 M

C.) molar solubility of barium carbonate = 1.96 x 10-8 M


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