In: Statistics and Probability
Find a 95% confidence interval for the difference of two means when you have independent samples, both of size 36, from two populations, in which the variances are not known to be equal. In this case, n1=36, s12=8.2, the first sample mean is equal to 7.9; n2 =36, s22=10.4, the second sample mean is equal to 9.1
Interpret the interval once you find it. Namely, can you conclude one mean is greater than the other mean and if so, which one? You do not have to develop the formula, but just use it.
Since 0 is contained in the above confidence interval we cannot conclude that one mean is greater than the other mean.
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