In: Chemistry
36.
What is the net ionic equation for the acid–base reaction of hydrobromic acid with sodium hydroxide?
A)
NaOH(aq) + HBr(aq) → H2O(l) + NaBr(aq)
B)
Na+(aq) + –OH(aq) + H+(aq) + Br–(aq) → H2O(l) + Na+(aq) + Br–(aq)
C)
Na+(aq) + –OH(aq) + H+(aq) + Br–(aq) → H+(aq) + –OH(aq) + Na+(aq) + Br–(aq)
D)
–OH(aq) + H+(aq) → H2O(l)
Which salt forms a basic solution when dissolved in water?
A) KCl B) NH4Br C) LiNO3 D) Na3PO4
44.
A solution containing a low concentration HCl is a weak acid.
A) True B) False
1st question : B
Net ionic equation for the acid–base reaction of hydrobromic acid with sodium hydroxide
NaOH is strong base, so it will be completely dissociated in the solution.
NaOH <==> Na+ + OH-
HBr is a strong base, it will be completely dissociated in the solution:
HBr <==> H+ + Br-
The ions will react to form H2O and salt. NaBr is an electrolyte, so it will be completely dissociated into ions. So the net reaction will be:
B) Na+(aq) + OH-(aq) + H+(aq) + Br–(aq) → H2O(l) + Na+(aq) + Br–(aq)
2nd Question: d
a. KCl is a salt of strong base KOH and strong acid HCl. Thus in sloution after hydrolysis of KCl, KOH and HCl will be formed . The strong base and strong acid will neutralize each other, making the pH of the solution 7.
b. NH4Br is a salt of weak acid NH4OH and strong acid HBr.
NH4Br + H2O = NH4OH + HBr = NH4OH + H+ + Br-
HBr will be completely dissociated as it is a strong acd. Thus solution of NH4Br will be acidic
c. LiNO3 + H2O = LiOH + HNO3 = Li+ + NO3- + H2O
LiOH is a strong base and HNO3 is a strong acid. Thus solution will be neutral.
d. Na3PO4 + 3H2O = H3PO4 + 3NaOH = H3PO4 + 3Na+ + 3OH-
H3PO4 is weak base. NaOH will be completely dissociated in the solution making the solution basic.
3rd question : False
A weak acid is an acid that dissociates incompletely, releasing only some of its hydrogen atoms into the solution.
Thus dilution solution of a strong acid does not mean it is a weak acid. Whatever the concentration is, solution of HCl is always a strong acid as it is dissociated completely in the solution.