In: Statistics and Probability
Many food manufacturers fortify their food products by adding vitamins. The following data are the amounts of vitamin C measured in mg/100g of corn soy blend for a random sample of size 8.
Sample points: 26 31 23 22 11 22 14 31
The US Agency for International Development specifies a mean vitamin C content of 30 mg. Test the hypothesis that mean vitamin C content does not conform to these specifications at significance level 5%.
(s=7.19)
Decision: [ Select ] ["Reject the null hypothesis.", "Do not reject the null hypothesis."]
Solution:
x | x2 |
26 | 676 |
31 | 961 |
23 | 529 |
22 | 484 |
11 | 121 |
22 | 484 |
14 | 196 |
31 | 961 |
∑x=180 | ∑x2=4412 |
Mean ˉx=∑xn
=26+31+23+22+11+22+14+31/8
=180/8
=22.5
= 30
=22.5
S =7.19
n = 8
This is the two tailed test .
The null and alternative hypothesis is ,
H0 : = 30
Ha : 30
Test statistic = t
= ( - ) / S / n
= (22.5-30) / 7.19 / 8
= −2.95
Test statistic = t = −2.95
P-value =0.0214
= 0.05
P-value <
0.0214 < 0.05
Reject the null hypothesis .
There is sufficient evidence to claim that the population mean μ is different than 30, at the 0.05 significance level.