Question

In: Chemistry

Please anwer fast!! Please give work, please don't comment your a tutor and to email you....

Please anwer fast!!
Please give work, please don't comment your a tutor and to email you. Please help me!! I know the answer is 5.53 but I need the calculations/work to correctly work through this problem correctly! Will rate better than lifesaver I need you chemistry genius's!!!

Confirm by calculation that the pH of CO2 saturated waterat 25C is 5.6, given that the CO2 concentration in air is 390 ppm. For CO2 Henry's constant is 3.4*10^(-2)M atm^(-) at 25C. The Ka for H2CO3 is 4.5*10^(-7) at that temp. (b) Recalculate the pH for a CO2 concentration of 560ppm, ie, double that of the pre-industrial age.

Solutions

Expert Solution

Molecular weight of air = 29

CO2 = 390ppm = 0.39gm of CO2 per kg of air*1/44.01 mol/gm of CO2=

0.00886 mol CO2 per kg of air =

0.00886*10^-3 per gm of air*29 gm/mol =

0.000257mol of CO2 per mole of air

Mole fraction of CO2 =

0.000257

Partial pressure of CO2 = 1atm*0.000257 = 0.000257atm

pco2 = M/KHcp

M = pco2*KHcp = 3.4*10^(-2)*.000257 = 8.74*10^(-6)M

H2CO3=8.74*10^(-6)

H2CO3 = H+ + HCO3-

H+ = HCO3-

Ka=(H+)^2/H2CO3 =4.5*10^(-7)

H^2 = 8.74*10^(-6)*4.5*10^(-7)

H=1.98*10^(-6)

pH = 5.7

(b) Recalculate the pH for a CO2 concentration of 560ppm, ie, double that of the pre-industrial age.

CO2 = 560ppm =

0.56gm of CO2 per kg of air*1/44.01 mol/gm of CO2=

0.0127mol CO2 per kg of air =

0.0127*10^-3 per gm of air*29 gm/mol =

0.000369mol of CO2 per mole of air

Mole fraction of CO2 =

0.000369

Partial pressure of CO2 = 1atm*0.000369 = 0.000369atm

pco2 = M/KHcp

M = pco2*KHcp = 3.4*10^(-2)*.000369 = 12.546*10^(-6)M

H2CO3=8.74*10^(-6)

H2CO3 = H+ + HCO3-

H+ = HCO3-

Ka=(H+)^2/H2CO3 =4.5*10^(-7)

H^2 = 12.546*10^(-6)*4.5*10^(-7)

H=2.376*10^(-6)

pH = 5.6


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