Q−3: [5×4 marks]
a. Find a, b if a+2b=107 mod 9 and 2a+b=-55 mod 7.
b. Write the prime factorization of 229320 and 49140, hence find
GCD and LCM.
c. Convert the following number (1303)4 to base 5.
d. Using the Prime Factorization technique determine whether 173 is
a prime.
e. Use the cipher: f(x)=(x+7) mod 26 to decrypt “THAO ALZA”.
Calculate the mass defect of the boron nucleus 11 5B. The mass
of neutral 11 5B is equal to 11.009305 atomic mass units. Express
your answer in atomic mass units to four significant figures.
Part B
Calculate the binding energy E of the boron nucleus 11 5B
(1eV=1.602×10−19J). Express your answer in millions of electron
volts to four significant figures.
Part C
Calculate the binding energy per nucleon of the boron nucleus 11
5B. Express your answer in millions of...
The system: 2A + B ↔ 2C ; initially started with 1 mole of B and
1 mol A in a 1L flask. Keq = 6.8 x 10-5 To
calculate the equilibrium concentrations a simplifying assumption
(approximation) can be made.
True
False
Let A and B be two events. Find the largest and smallest
possible values P(A U B) can take in terms of P(A) and P(B) and
give examples in which these values can be attained.
When 2A (g) <-----> B(g) + C(g) [exothermic] is at
equilibrium the concentration of B
a. increase
b. decreases
c. is unchanged
d. changes randomly
e. cannot predict
Concentration of C is increased, concentration of A
a. increase
b. decreases
c. is unchanged
d. changes randomly
e. cannot predict
Concentration of C is increased, concentration of B
a. increase
b. decreases
c. is unchanged
d. changes randomly
e. cannot predict
If temp is raised the concentration of C
a. increase...
Given
a=3-2i
b=-2+3i
Find 2a+3b and;
i) state the real part (in Box 1)
ii) state the imaginary part (in Box 2 and without the
i).
Question 2 options:
Blank # 1
Blank # 2
Given the following reactions, what is the overall reaction and
the ∆Hrxn
2A + B → A2B
∆H° = – 25.0 kJ/mol
2A2B → 2AB + A2
AB2 → Α + 2Β
∆H° = 35.0 kJ/mol
∆H° = – 15.0 kJ/mol
A) A + A2B → AB + A2
∆Hrxn = +5 kJ/mol
B) 2A + B + 2A2B + AB2 →
A2B + 2AB + A2 + A + B
∆Hrxn = -5 kJ/mol
C) A + A2B → AB + A3
∆Hrxn...
Chemical kinetics
For the reaction 2A + B → C + D + 2E, data for a run with
[A]0 = 800 mmol/L and [B]0 = 2.00 mmol/L
are
t/ks
8
14
20
30
50
90
[B]/[B]0
0.836
.745
.680
.582
.452
.318
and data for a run with [A]0 = 600 mmol/L and
[B]0 = 2.00 mmol/L are
t/ks
8
20
50
90
[B]/[B]0
0.901
0.787
0.598
0.453
Find the order with respect to each reactant (A and B)...