In: Statistics and Probability
consider a normally distributed random variable with a population mean of 190 and a standard deviation of 24. A sample mean of 36 observations will be taken the probability that the sample mean will be between 196 and 198 is?
Solution :
Given that,
mean =
= 190
standard deviation =
= 24
=
/
n = 24 /
36 = 4
= P[(196 - 190) /4 < (
-
)
/
< (198 - 190) / 4)]
= P(1.5 < Z < 2)
= P(Z < 2) - P(Z < 1.5)
= 0.9772 - 0.9332
= 0.044
Probability = 0.044