consider a normally distributed random variable with a population mean of 190 and a standard deviation...

consider a normally distributed random variable with a population mean of 190 and a standard deviation of 24. A sample mean of 36 observations will be taken the probability that the sample mean will be between 196 and 198 is?

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Expert Solution

Solution :

Given that,

mean = = 190

standard deviation = = 24

= / n = 24 / 36 = 4

= P[(196 - 190) /4 < ( - ) / < (198 - 190) / 4)]

= P(1.5 < Z < 2)

= P(Z < 2) - P(Z < 1.5)

= 0.9772 - 0.9332

= 0.044

Probability = 0.044

orchestra answered 1 year ago

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