Question

The data show the bug chirps per minute at different temperatures. Find the regression​ equation, letting the first variable be the independent​ (x) variable. Find the best predicted temperature for a time when a bug is chirping at the rate of 3000 chirps per minute. Use a significance level of 0.05. What is wrong with this predicted​ value?

Chirps in 1 min	1133	1037	1230	854	1157	894
Temperature ​(degrees°​F)	85.4	86.6	92.1	74.2	85.5	79.5

What is the regression​ equation?

​(Round the​ x-coefficient to four decimal places as needed. Round the constant to two decimal places as​ needed.)

What is the best predicted temperature for a time when a bug is chirping at the rate of 3000 chirps per​ minute?The best predicted temperature when a bug is chirping at 3000 chirps per minute is _____degrees°F.

​(Round to one decimal place as​ needed.)

What is wrong with this predicted​ value? Choose the correct answer below.

A. It is unrealistically high. The value 3000 is far outside of the range of observed values.

B. It is only an approximation. An unrounded value would be considered accurate.

C. The first variable should have been the dependent variable.

D. Nothing is wrong with this value. It can be treated as an accurate prediction.

Answer 1

Regression Analysis
	r²	0.853
	r	0.924
	Std. Error	2.658
	n	6
	k	1
	Dep. Var.	Temperatures
ANOVA table
Source	SS	df	MS	F	p-value
Regression	164.5282	1	164.5282	23.29	.0085
Residual	28.2601	4	7.0650
Total	192.7883	5
Regression output				confidence interval
variables	coefficients	std. error	t (df=4)	p-value	95% lower	95% upper
Intercept	43.9017	8.36	5.25	0.01	20.70	67.10
Chirps	0.0380	0.0079	4.826	.0085	0.0162	0.0599

What is the regression​ equation?

y= 43.90+0.0380x

​(Round the​ x-coefficient to four decimal places as needed. Round the constant to two decimal places as​ needed.)

What is the best predicted temperature for a time when a bug is chirping at the rate of 3000 chirps per​ minute?The best predicted temperature when a bug is chirping at 3000 chirps per minute is 158.0 degrees°F.

​(Round to one decimal place as​ needed.)

What is wrong with this predicted​ value? Choose the correct answer below.

C. The first variable should have been the dependent variable.