In: Chemistry
In a redox reaction with 2.0301 g of benzaldehyde and 1.8 g of KOH, benzoic acid(aqueous layer), and benzyl alcohol(organic layer) was obtained. Calculate the theoretical yield for the benzoic acid and benzyl alcohol.
Balanced reaction is given above.
Now,
Moles of Benzaldehyde = ( mass/ molar mass)
= (2.0301/106)
= 0.019.
Moles of KOH = (mass / molar mass)
= ( 1.8/56)
= 0.032.
Benzaldehyde and KOH reacts in 2:1 mole ratio hence limitimg reactant is Benzaldehyde
So, moles of Benzaldehyde reacts = 0.019
Mole ratio of Benzaldehyde and Benzoic acid = 2:1
Mole ratio of Benzaldehyde and Benzyl alcohol = 2:1
Hence, moles of Benzoic acid = (0.019/2) = 0.0095
Mass of Benzoic acid ( theoretical yield)
= moles × molar mass
= 0.0095×122 = 1.159 g.
Moles of benzyl alcohol
=( 0.019/2 ) = 0.0095
Mass of benzyl alcohol (theoretical yield)
= (0.0095 × 108)
= 1.026 g.