In a redox reaction with 2.0301 g of benzaldehyde and 1.8 g of KOH, benzoic acid(aqueous...

In a redox reaction with 2.0301 g of benzaldehyde and 1.8 g of KOH, benzoic acid(aqueous layer), and benzyl alcohol(organic layer) was obtained. Calculate the theoretical yield for the benzoic acid and benzyl alcohol.

Solutions

Expert Solution

Balanced reaction is given above.

Now,

Moles of Benzaldehyde = ( mass/ molar mass)

= (2.0301/106)

= 0.019.

Moles of KOH = (mass / molar mass)

= ( 1.8/56)

= 0.032.

Benzaldehyde and KOH reacts in 2:1 mole ratio hence limitimg reactant is Benzaldehyde

So, moles of Benzaldehyde reacts = 0.019

Mole ratio of Benzaldehyde and Benzoic acid = 2:1

Mole ratio of Benzaldehyde and Benzyl alcohol = 2:1

Hence, moles of Benzoic acid = (0.019/2) = 0.0095

Mass of Benzoic acid ( theoretical yield)

= moles × molar mass

= 0.0095×122 = 1.159 g.

Moles of benzyl alcohol

=( 0.019/2 ) = 0.0095

Mass of benzyl alcohol (theoretical yield)

= (0.0095 × 108)

= 1.026 g.

queen_honey_blossom answered 2 years ago

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