In: Chemistry
Use the half-reaction method to balance each redox reaction occurring in acidic aqueous solution. |
Part A PbO2(s)+I−(aq)⟶Pb2+(aq)+I2(s) Express your answer as a chemical equation. Identify all of the phases in your answer.
SubmitMy AnswersGive Up Part B SO32−(aq)+MnO4−(aq)→SO42−(aq)+Mn2+(aq) Express your answer as a chemical equation. Identify all of the phases in your answer.
SubmitMy AnswersGive Up Part C S2O32−(aq)+Cl2(g)→SO42−(aq)+Cl−(aq) Express your answer as a chemical equation. Identify all of the phases in your answer.
SubmitMy AnswersGive Up |
A)
PbO2(s)+I−(aq)⟶Pb2+(aq)+I2(s)
split
PbO2 = Pb+2
I- = I2
balance
PbO2 = Pb+2
2I- = I2
add H2O
PbO2 = Pb+2 + 2H2O
2I- = I2
add H
4H+ + PbO2 = Pb+2 + 2H2O
2I- = I2
balance charge
2e- + 4H+ + PbO2 = Pb+2 + 2H2O
2I- = I2 + 2e-
balance and add all
2I- + 2e- + 4H+ + PbO2 = Pb+2 + 2H2O + I2 + 2e-
cancel common terms
2I- +4H+ + PbO2 = Pb+2 + 2H2O + I2
add phases
2I-(aq) +4H+(aq) + PbO2(s) = Pb+2(aq) + 2H2O(l) + I2(s)
Q2.
SO32−(aq)+MnO4−(aq)→SO42−(aq)+Mn2+(aq)
split
SO3-2 = SO4-2
MnO4- = Mn+2
balance O
H2O + SO3-2 = SO4-2
MnO4- = Mn+2 + 4H2O
balance H
H2O + SO3-2 = SO4-2 + 2H+
8H+ + MnO4- = Mn+2 + 4H2O
balance charge
H2O + SO3-2 = SO4-2 + 2H+ + 2e-
5e- + 8H+ + MnO4- = Mn+2 + 4H2O
balanc e-
5H2O + 5SO3-2 = 5SO4-2 + 10H+ + 10e-
10e- + 16H+ + 2MnO4- = 2Mn+2 + 8H2O
add all
10e- + 16H+ + 2MnO4- + 5H2O + 5SO3-2 = 5SO4-2 + 10H+ + 10e- + 2Mn+2 + 8H2O
simplify
6H+ + 2MnO4- + 5SO3-2 = 5SO4-2 + 2Mn+2 + 3H2O
add phases
6H+(aq) + 2MnO4-(aq) + 5SO3-2(aq) = 5SO4-2(aq) + 2Mn+2(aq) + 3H2O(l)
c)
S2O32−(aq)+Cl2(g)→SO42−(aq)+Cl−(aq)
S2O3-2 = SO4-2
Cl2 = Cl-
balance
S2O3-2 = 2SO4-2
Cl2 = 2Cl-
balance O
2H2O + S2O3-2 = 2SO4-2
Cl2 = 2Cl-
balance H
2H2O + S2O3-2 = 2SO4-2 + 4H+
Cl2 = 2Cl-
balance charge
2H2O + S2O3-2 = 2SO4-2 + 4H+ + 2e-
2e- + Cl2 = 2Cl-
add all
2e- + Cl2 + 2H2O + S2O3-2 = 2SO4-2 + 4H+ + 2e- + 2Cl-
simplify
Cl2 + 2H2O + S2O3-2 = 2SO4-2 + 4H+ + 2Cl-
add phases
Cl2(aq) + 2H2O(l) + S2O3-2(aq) = 2SO4-2(aq) + 4H+(aq) + 2Cl-(aq)