Solid zinc acetate is slowly added to 50.0 mL of a 0.0347 M ammonium carbonate solution....

Solid zinc acetate is slowly added to 50.0 mL of a 0.0347 M ammonium carbonate solution. The concentration of zinc ion required to just initiate precipitation is

____M.

Solutions

Expert Solution

Ksp of zinc carbonate, ZnCO3, is 1.46 x 10-11

ZnCO3 ---> Zn⁺² + CO₃^-2

Let solubility of ZnCO3= s

[Zn⁺²] = s (due to Zinc carbonate)

[CO₃^-2]= s (due to Zinc carbonate)

The cocentration of [CO₃^-2]= 0.0347 M (due to Ammonium carbonate)

Ksp = [Zn⁺²] [CO₃^-2]

so the concentration of Zn⁺² required to initiate precipitation will be

[Zn⁺²] = Ksp / [CO₃^-2] = 1.46 X 10^-11 / (s + 0.0347)

We can ignore s in deonimator as Ksp is very low

[Zn⁺²] = 1.46 X 10^-11 / 0.0347 = 4.207 X 10^-10 M

the concentration of Zn⁺² required to initiate precipitation will be 4.207 X 10^-10 M

queen_honey_blossom answered 1 year ago

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