Question

In: Statistics and Probability

In 2019, the average weight of baby quails was 110 grams. Pollution levels in Quails natural...

In 2019, the average weight of baby quails was 110 grams. Pollution levels in Quails natural habit has increased and a conservation group wants to know if the average weight of baby quails has reduced. A sample of 49 baby quails yielded a sample mean of 108 grams. Historical data shows that the population standard deviation is 10 grams.

At the 5% level of significance, can the conservation group conclude that baby quails have become lighter?

Would your answer change at a 1% level of significance? Justify.

Solutions

Expert Solution

Solution :

= 110

=108

=10

n = 49

This is the right tailed test .

The null and alternative hypothesis is ,

H0 :   = 110

Ha : > 110

Test statistic = z

= ( - ) / / n

= (108-110) / 10 / 49

= -1.4

P(z >-1.4 ) = 1 - P(z < -1.4 ) =1- 0.0808=0.9192

P-value = 0.9192

= 0.05  

the null hypothesis is not rejected.

P-value >

Reject the null hypothesis .

There is sufficient evidence to suggest that   

It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the population mean \muμ is greater than 110, at the 0.05 significance level

(b)

1% level of significance Justify.

It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the population mean \muμ is greater than 110, at the 0.01 significance level


Related Solutions

A random sample of 80 baby boys, show they weighed 3000 grams on average with a...
A random sample of 80 baby boys, show they weighed 3000 grams on average with a standard deviation of 100, at birth. While a random sample of 60 baby girls show they weighed 2800 grams on average with a standard deviation of 70. In order to test the hypothesis that if baby boys and girls weights have the same variance or not, what is the value of test statistic? A) 2.041 B) 0.490 C) 0.7 D) 1.429
A baby food company claims that on the average the product contains 6.0 grams of protein...
A baby food company claims that on the average the product contains 6.0 grams of protein per bottle. A random sample of 14 bottles of the product was taken and the protein measurements are as follows. 5.1 4.9 6.0 6.4 5.7 4.8 6.2 6.0 5.9 5.6 5.5 5.8 5.3 (i) Find the sample mean x¯ and the sample standard deviation s. (ii) Assume that the protein content per bottle obeys an N (µ, σ2) distribution with σ unknown. Give the...
A fast-food restaurant uses an average of 110 grams of meat per burger patty. Suppose the...
A fast-food restaurant uses an average of 110 grams of meat per burger patty. Suppose the amount of meat in a burger patty is normally distributed with a standard deviation of 20 grams. What is the probability that the average amount of meat in four randomly selected burgers is less than 105 grams?
1) The average weight of a certain machined part is 475 grams, with a standard deviation...
1) The average weight of a certain machined part is 475 grams, with a standard deviation of 5 grams. a) What is the probability that a randomly selected part from the manufacturing line weighs less than 477 grams? b) What is the probability that a randomly selected part from the manufacturing line weighs less than 472 grams? c) What is the probability that a randomly selected part from the manufacturing line weighs at least 482 grams? d) What is the...
You measure 29 turtles' weights, and find they have an average weight of 56 grams. Assume...
You measure 29 turtles' weights, and find they have an average weight of 56 grams. Assume the population standard deviation is 5 grams. Based on this, what is the margin of error associated with a 90% confidence interval for the true population mean turtle weight. The sample size is sufficiently large that the normal distribution value can be used in deriving the margin of error. Give your answer as a decimal, to two places ± ______ grams
You measure 44 watermelons' weights, and find they have an average weight of 54 grams. Assume...
You measure 44 watermelons' weights, and find they have an average weight of 54 grams. Assume the population standard deviation is 4.8 grams. Based on this, what is the margin of error associated with a 99% confidence interval for the true population mean watermelon weight. The sample size is sufficiently large that the normal distribution value can be used in deriving the margin of error. Give your answer as a decimal, to two places
You measure 27 backpacks' weights, and find they have an average weight of 57 grams. Assume...
You measure 27 backpacks' weights, and find they have an average weight of 57 grams. Assume the population standard deviation is 5 grams. Based on this, what is the margin of error associated with a 99% confidence interval for the true population mean backpack weight. The sample size is sufficiently large that the normal distribution value can be used in deriving the margin of error.
Research Question: Is the average weight (in grams) of all Emerald Ash Borer Beetle less than...
Research Question: Is the average weight (in grams) of all Emerald Ash Borer Beetle less than 3. To help, my Uncle Superfly (who happens to be a biologist) took a random sample of n=10 beetles from my back yard and recorded their weights. They are: 1.5, 2, 3.5, 2.5, 1.5, 1.5, 2.5, 2, 2.5, 3
Calculate the total grams of Pt in 110 kg of an alloy that is composed of...
Calculate the total grams of Pt in 110 kg of an alloy that is composed of 86.5 at% Pt and 13.5 at% Ag.
Baby weight: Following are weights, in pounds, of 10 two-month-old baby girls. It is reasonable to...
Baby weight: Following are weights, in pounds, of 10 two-month-old baby girls. It is reasonable to assume that the population is approximately normal. 12.66 8.63 11.87 14.13 12.32 9.34 10.30 12.34 12.23 11.48 Construct a 90% interval for the mean weight of two-month-old baby girls. Round the answers to three decimal places. ____< u <_____
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT