In: Statistics and Probability
Baby weight: Following are weights, in pounds, of 10 two-month-old baby girls. It is reasonable to assume that the population is approximately normal.
12.66 8.63 11.87 14.13 12.32 9.34 10.30 12.34 12.23 11.48
Construct a 90% interval for the mean weight of two-month-old baby girls. Round the answers to three decimal places.
____< u <_____
Solution:
x | x2 |
12.66 | 160.2756 |
8.63 | 74.4769 |
11.87 | 140.8969 |
14.13 | 199.6569 |
12.32 | 151.7824 |
9.34 | 87.2356 |
10.3 | 106.09 |
12.34 | 152.2756 |
12.23 | 149.5729 |
11.48 | 131.7904 |
∑x=115.3 | ∑x2=1354.0532 |
Mean ˉx=∑xn
=12.66+8.63+11.87+14.13+12.32+9.34+10.3+12.34+12.23+11.48 /
10
=115.3/10
=11.53
Sample Standard deviation S=√∑x2-(∑x)2nn-1
=√1354.0532-(115.3)210/9
=√1354.0532-1329.409/9
=√24.6442/9
=√2.7382
=1.6548
Degrees of freedom = df = n - 1 = 10 - 1 = 9
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
t /2,df = t0.05,9 =1.833
Margin of error = E = t/2,df * (s /n)
=1.833 * (1.65 / 10)
= 0.96
Margin of error = 0.96
The 90% confidence interval estimate of the population mean is,
- E < < + E
11.53 - 0.96 < < 11.53 + 0.96
10.57 < < 3.70
(10.57, 12.49 )