In: Statistics and Probability
A fast-food restaurant uses an average of 110 grams of meat per burger patty. Suppose the amount of meat in a burger patty is normally distributed with a standard deviation of 20 grams. What is the probability that the average amount of meat in four randomly selected burgers is less than 105 grams?
Solution :
Given that ,
mean = = 110
standard deviation = = 20
P(x < 105 ) = P[(x - ) / < (105 - 110) / 20]
= P(z < - 0.25)
= 0.4013, Probability = 0.4013