Question

U can use data set of your own

1. Write a short paragraph discussing the chart and whether your hypothesis is consistent with the chart (what did you think prior to looking at the data, has that changed given now you have the data?).

Answer 1

Summary Table for Live Births
Mean	6206.33
Median	4260.50
Standard Deviation	7419.47
Minimum	444
Maximum	42836

Determine if there is sufficient evidence to conclude the average amount of births is over 8000 in the United States and territories at the 0.05 level of significance.

Clearly state a null and alternative hypothesis.

The null and alternative hypothesis are:

The null hypothesis, Ho: µ = 8000.

The average amount of births is 8000.

The alternative hypothesis, H1: µ> 8000.

The average amount of births is more than 8000.

Give the value of the test statistic.

We are given with:

Sample mean, x = 6206.33

Standard Deviation, s = 7419.47

Significance level, α = 0.05

Sample size, n = 52

Degree of freedom, df = n - 1 = 52 – 1 = 51

Test statistic, t = (x - µ)/s/ Ön

                        = (6206.33 – 8000)/7419.47/Ö52

                        = (-1793.67)/7419.47/Ö52

                        = - 1.743

Report the P-Value.

P-value with df = 51 and test statistic = -1.743 at α = 0.05 is, 0.0437.

Clearly state your conclusion (Reject the Null or Fail to Reject the Null)

Since p-value is less than the significance level, we can reject the null hypothesis. 0.0437<0.05.

Explain what your conclusion means in context of the data.

Therefore, we have sufficient evidence to say that the average amount of births is more than 8000.