In: Statistics and Probability
one can calculate the 95% confidence interval for the mean with the population standard deviation knowing this gives us an upper and lower confidence limit what happens if we decide to calculate the 99% confidence interval describe how the increase in the confidence level has changed the width of the confidence interval
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ANSWER:
For 95% confidence:
Note that
Lower Bound = X - z(alpha/2) * s / sqrt(n)
Upper Bound = X + z(alpha/2) * s / sqrt(n)
where
alpha/2 = (1 - confidence level)/2 = 0.025
X = sample mean = 100
z(alpha/2) = critical z for the confidence interval =
1.959963985
s = sample standard deviation = 30
n = sample size = 50
Thus,
Lower bound = 91.68457705
Upper bound = 108.3154229
Thus, the confidence interval is
( 91.68457705 ,
108.3154229 ) [ANSWER]
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For a 99% confidence:
Note that
Lower Bound = X - z(alpha/2) * s / sqrt(n)
Upper Bound = X + z(alpha/2) * s / sqrt(n)
where
alpha/2 = (1 - confidence level)/2 = 0.005
X = sample mean = 100
z(alpha/2) = critical z for the confidence interval =
2.575829304
s = sample standard deviation = 30
n = sample size = 50
Thus,
Lower bound = 89.07168179
Upper bound = 110.9283182
Thus, the confidence interval is
( 89.07168179 ,
110.9283182 ) [ANSWER]
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As we can see, the 99% confidence interval is WIDER than that of 95%.
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