In: Statistics and Probability
A cognitive psychologist working in the area of suggestion asked
a sample of children to solve as many problems as they could in 10
minutes. Half of the children are told that this is a
problem-solving task and the other half are told that this is just
a time-filling task. The psychologist hypothesizes that thinking it
is a problem-solving task will improve problem solving. What can be
concluded with an α of 0.05? Below is the data for the number of
problems solved.
problem-solving | time-filling |
3 4 5 4 2 6 4 |
10 5 8 7 6 8 7 |
a) What is the appropriate test
statistic?
---Select--- na z-test One-Sample t-test Independent-Samples t-test
Related-Samples t-test
b.Condition 1:
---Select--- suggestion the children problems solved
problem-solving time-filling
Condition 2:
---Select--- suggestion the children problems solved
problem-solving time-filling
c) Obtain/compute the appropriate values to
make a decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses
to help solve the problem.)
critical value = ; test statistic =
Decision: ---Select--- Reject H0 Fail to reject
H0
d) If appropriate, compute the CI. If not
appropriate, input "na" for both spaces below.
[ , ]
e) Compute the corresponding effect size(s) and
indicate magnitude(s).
If not appropriate, input and/or select "na" below.
d = ; ---Select--- na trivial effect
small effect medium effect large effect
r2 = ; ---Select--- na
trivial effect small effect medium effect large effect
f) Make an interpretation based on the results.
Children that were told this is a problem-solving task solved significantly more problems than children that were told this is a time-filling task.Children that were told this is a problem-solving task solved significantly less problems than children that were told this is a time-filling task. The suggestions had no significant impact on problem solving.
Answer:-
Given That:-
A cognitive psychologist working in the area of suggestion asked a sample of children to solve as many problems as they could in 10 minutes. Half of the children are told that this is a problem-solving task and the other half are told that this is just a time-filling task
a) What is the appropriate test statistic?
---Select--- na z-test One-Sample t-test Independent-Samples t-test
Related-Samples t-test
Independent-Samples t-test
b.Condition 1:
---Select--- suggestion the children problems solved
problem-solving time-filling
Condition 2:
---Select--- suggestion the children problems solved
problem-solving time-filling
condition 1 : problem solving
condition 2: time filling
c) Obtain/compute the appropriate values to make a
decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses
to help solve the problem.)
critical value = ; test statistic =
Decision: ---Select--- Reject H0 Fail to reject
H0
Sample #1 ----> 1
mean of sample 1,
x̅1= 4.286
standard deviation of sample 1, s1 = 1.704
size of sample 1, n1= 7
Sample #2 ----> 2
mean of sample 2,
x̅2= 7.286
standard deviation of sample 2, s2 = 1.604
size of sample 2, n2= 7
difference in sample means = x̅1-x̅2
= 4.2857 - 7.3
= -3.00
pooled std dev , Sp=
= 1.6547
std error , SE =
= 0.8845
t-statistic = ((x̅1-x̅2)-µd)/SE)
= ( -3.0000 - 0) / 0.88
= -3.3918
Degree of freedom, DF= n1+n2-2
= 12
t-critical value , t* = 2.179 (excel formula =t.inv(α/2,df)
decision: Reject Ho
d) If appropriate, compute the CI. If not appropriate,
input "na" for both spaces below.
[ , ]
Degree of freedom, DF= n1+n2-2
= 12
t-critical value = t α/2 = 2.1788 (excel formula
=t.inv(α/2,df)
pooled std dev , Sp=
= 1.6547
std error , SE =
= 0.8845
margin of error, E = t*SE
= 2.1788 * 0.88
=1.93
difference of means = x̅1-x̅2
= 4.2857 - 7.286
= -3.0000
confidence interval is
Interval Lower Limit= (x̅1-x̅2) - E
= -3.0000 - 1.9271
= -4.927
Interval Upper Limit= (x̅1-x̅2) + E
= -3.0000 + 1.9271
= -1.073
e) Compute the corresponding effect size(s) and indicate
magnitude(s).
If not appropriate, input and/or select "na" below.
d = ; ---Select--- na trivial effect
small effect medium effect large effect
r2 = ; ---Select--- na trivial
effect small effect medium effect large effect
effect size,
cohen's d = |(x̅1-x̅2 )/Sp |
= 1.8130 (large)
r²= 0.489 (large)
f) Make an interpretation based on the results. Children that were told this is a problem-solving task solved significantly more problems than children that were told this is a time-filling task.Children that were told this is a problem-solving task solved significantly less problems than children that were told this is a time-filling task. The suggestions had no significant impact on problem solving.
Children that were told this is a problem-solving task solved significantly less problems than children that were told this is a time-filling task.
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