Question

In: Statistics and Probability

For the following probability mass function, p(x)=1/x for x=2, 4, 8 p(x) = k/x2 for x=16...

For the following probability mass function, p(x)=1/x for x=2, 4, 8 p(x) = k/x2 for x=16 Find the value of k. Find the standard deviation of (7-9X).

Solutions

Expert Solution

1) for this to be valid:

P(x) must be equal to 1

therefore P(x) =P(2)+P(4)+P(8)+P(16)=(1/2)+(1/4)+(1/8)+k/256 =1

k/256 =1/8

k=32

2)

x P(x) xP(x) x2P(x)
2    1/2 1.0000 2.0000
4    1/4 1.0000 4.0000
8    1/8 1.0000 8.0000
16    1/8 2.0000 32.0000
total 5.0000 46.0000
E(x) =μ= ΣxP(x) = 5.0000
E(x2) = Σx2P(x) = 46.0000
Var(x)=σ2 = E(x2)-(E(x))2= 21.0000
std deviation=         σ= √σ2 = 4.5826

hence standard deviation of 7-9X =9*SD(X) =9*4.5826 =41.2432


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