In: Math
A and B together can complete a piece of work in 20 days. B and C together can complete in 30 days. If A is twice as good a workman as C, then in how many days will B alone can complete the same work?
Solution: A+B’s 1 day’s work = 1/20
B+C’s 1 day’s work = 1/30
Since, A is twice as good a workman as C.
∴ A = 2C
B+2C = 1/20
C = 1/20 - 1/30 = 1/60
B can complete the same work = 1/30 - 1/60 = 1/60 = 60 Days
60 days