In: Biology
For the given situation above, lets height is presented by genotype T for tall and t for short and seed colour is presented by genotype G for green and g for yellow seed colour.
the genotype of the parent - TTGG( Homozygous Tall /Green) X ttgg(Homozygous Short/Yellow)
Both the parents will produce a single type of gametes each i.e. TG type from Homozygous Tall /Green and tg type from Homozygous Short/Yellow.
The cross will produce F1 generation which will show TtGg genotype and heterozygous Tall/Green phenotype.
The offspring from F1 generation will produce different kinds of gametes i.e. TG, Tg, tG, tg
When we'll self cross the F1 generation the following fill be observed
| TG | Tg | tG | tg | |
| TG | TTGG | TTGg | TtGG | TtGg |
| Tg | TTGg | TTgg | TtGg | Ttgg |
| tG | TtGG | TtGg | ttGG | ttGg |
| tg | TtGg | Ttgg | ttGg | ttgg |
TTGG - Tall /Green
TTGg - Tall /Green
TtGG - Tall /Green
TtGg - Tall /Green
TTGg - Tall /Green
TTgg - Tall/Yellow
TtGg - Tall /Green
Ttgg - Tall/yellow
TtGG - Tall/Green
TtGg - Tall /Green
ttGG - short/Green
ttGg - Short/Green
TtGg - Tall /Green
Ttgg - Tall/Yellow
ttGg - Short/ Green
ttgg - Short/Yellow
From the above cross in F2 generation total 4 types of phenotypes were observed i.e. Tall/Green, Tall/Yellow, Short/Green, Short/Yellow in 9:3:3:1 ratio.