In: Biology
For the given situation above, lets height is presented by genotype T for tall and t for short and seed colour is presented by genotype G for green and g for yellow seed colour.
the genotype of the parent - TTGG( Homozygous Tall /Green) X ttgg(Homozygous Short/Yellow)
Both the parents will produce a single type of gametes each i.e. TG type from Homozygous Tall /Green and tg type from Homozygous Short/Yellow.
The cross will produce F1 generation which will show TtGg genotype and heterozygous Tall/Green phenotype.
The offspring from F1 generation will produce different kinds of gametes i.e. TG, Tg, tG, tg
When we'll self cross the F1 generation the following fill be observed
TG | Tg | tG | tg | |
TG | TTGG | TTGg | TtGG | TtGg |
Tg | TTGg | TTgg | TtGg | Ttgg |
tG | TtGG | TtGg | ttGG | ttGg |
tg | TtGg | Ttgg | ttGg | ttgg |
TTGG - Tall /Green
TTGg - Tall /Green
TtGG - Tall /Green
TtGg - Tall /Green
TTGg - Tall /Green
TTgg - Tall/Yellow
TtGg - Tall /Green
Ttgg - Tall/yellow
TtGG - Tall/Green
TtGg - Tall /Green
ttGG - short/Green
ttGg - Short/Green
TtGg - Tall /Green
Ttgg - Tall/Yellow
ttGg - Short/ Green
ttgg - Short/Yellow
From the above cross in F2 generation total 4 types of phenotypes were observed i.e. Tall/Green, Tall/Yellow, Short/Green, Short/Yellow in 9:3:3:1 ratio.