Question

A 1000 MW power plant of 35% thermal efficiency is proposed. The plant burns 3% sulphur coal with a heating value of 6000 Kcal/kg and emits 64000 m3/min of flue gas. What is the concentration of SO2 in the flue gas in ppm? Assume that the density of SO2 is 1920 g/m3.

Answer 1

Solution:-

Given:- P = 1000x10³ KW = 1000x 10³ x 1000 x 3600 KWh

thermal Efficiency _th = 35%

heating Value = 6000Kcal/Kg =6000 x 4186.7 J/kg

Emission = 64000 m³/min

Density =1920 g/m³

So that,

amount of coal = P / Heating value

amount of Coal = 10⁹ x 3600/(6000 x4186. 7)

amount of coal = 143,310. 96Kg

Amount of coal for efficiency 35% = 143,310.96/0.35

Amount of coal For efficiency 35% = 409,459. 88 Kg

but plant burns 3% of sulpher coal, we get

So that sulpher amount in coal = 409,459.88 x 3/100

Sulpher amount = 12, 283.79 kg

By Conversion in ppm, we have

1 ppm = 0.001g/kg

So that amount of sulpher in ppm = 0.001/12,283.79

Amount of sulpher = 8.141 x 10^-8 PPM