Two possible nuclear fusion reactions are d + d → 4He + γ and d + d → 4He + p , where d is deuterium

Two possible nuclear fusion reactions are d + d → ⁴He + γ and d + d → ⁴He + p , where d is deuterium, an atom with a nucleus composed of a proton bound to a neutron. ³He and ⁴He are helium atoms with nuclei consisting of two protons and one neutron (³He) or two protons and two neutrons (⁴He). Both of these reactions satisfy energy conservation. Which do you think occurs more quickly and why?

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Expert Solution

Fusion reaction – Formation of one nucleus from two or more nuclei is called fusion reaction and it releases tremendous amount of energy in this process.

Einstein’s energy mass equation.

Energy (E) = mc2

Here, m is mass and is speed of light

Two possible nuclear fusion reactions are

d + d → 4He + γ

d + d → 3He + γ

Where, d is deuterium, He is helium atom and γ is Gamma.

Since, 4He has more mass than 3He.

So, according to Einstein’s mass equation. 4He Has more energy than 3He.

So, large amount of energy released in case of 3He and we know that spontaneous reaction releases more energy so, 3He occurs more quickly.

Hence, d + d → 3He + γ occurs more quickly because of spontaneity and releases more energy.

Junaid answered 2 years ago

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