In: Chemistry
EtOH+ NAD+ ---> Acetylaldehyde + NADH
initial concentrations: EtOH= 900uL (45.0mM ethanol in 50.0mM Tris Buffer)
NAD+= 900uL (0.290mM NAD+ in 50mM Tris)
ADH= 100uL (0.0503 g ADH in 7,000. uL) (doesn't apply to Keq equation)
The average absorbance at equilibrium for this mixture is 0.3602 at 342.7nm
My experimental molar extinction coefficient= 5281.2821 M-1 cm-1, path length=1cm
What is the equilibrium constant? Complete the ICE table and calculate the Keq of the reaction from the information provided.