In: Statistics and Probability
It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work in temperatures of 200–500°F. In a test of one type of mask, 11 of 55 masks had lenses pop out at 250°. Construct a 90% upper confidence bound for the true proportion of masks of this type whose lenses would pop out at 250°.
(a) Answer the question as given except find the 90% confidence interval estimate, not the 90% upper confidence bound.
(b) If we wanted a 90% confidence interval of width 10%, what sample size is required? (i) Assume we have no idea what the sample proportion will be. (ii) Assume we know the sample proportion will be about 20%.
First we construct the upper bound 90% confidence interval here:
From standard normal tables, we get:
P(Z < 1.282 ) = 0.9
The sample proportion here is computed as: p = 11/55 = 0.2
Therefore the upper bound here is computed as:
a) From standard normal tables, we get:
P(-1.65 < Z < 1.65 ) = 0.9
Therefore the confidence interval here is obtained as:
This is the required confidence interval here.
b) (i) For no prior proportion, we take p = 0.5 to be on the safe side.
The interval width is 10% which means margin of error is 10/2 = 5% that is 0.05
The margin of error is computed as:
Therefore 271 is the minimum sample size required here.
ii) Here, we are given a prior proportion value of p = 0.2, therefore the minimum sample size computed here is:
Therefore 174 is the minimum sample size required here.