Question

Part A MX (Ksp = 3.97×10−36)

S = _____ M

Part B Ag2CrO4 (Ksp = 1.12×10−12) Express your answer in moles per liter.

S = _____ M

Part C Ni(OH)2 (Ksp = 5.48×10−16) Express your answer in moles per liter.

S = _____ M

Answer 1

part-A

MX(s) --------------> M^+ (aq) + X^- (aq)

                               s                s

Ksp   = [M^+][X^-]

3.97*10^-36   = s*s

s^2               = 3.97*10^-36

s                = 2*10^-18 M

                    = 2*10^-18 mole/L

part-B

      Ag2CrO4(s) -----------------> 2Ag^+ (aq) + CrO4^2- (aq)

                                                  2s                      s

        Ksp      = [Ag^+]^2[CrO4^2-]

         1.12*10^-12   = (2s)^2*s

          4s^3                = 1.12*10^-12

               s               = 6.54*10^-5M

               s              = 6.54*10^-5 mole/L

part-c

      Ni(OH)2(s) --------------> Ni^2+ (aq) + 2OH^- (aq)

                                               s                    2s

          Ksp    = [Ni^2+]OH^-]^2

         5.48*10^-16   = s*(2s)^2

             4s^3              = 5.48*10^-16

                   s              = 5.15*10^-6M

                                   = 5.15*10^-6 mole/L