Question

For the circuit shown in the figure, find the current through and the potential difference across each resistor.

For the circuit shown in the figure, find the current through and the potential difference across each resistor.

Answer 1

from the figure

5ohm and 10 ohm are in series which leads to 15 ohms

slly

6ohm and 4 ohm are in series which leads to 10 ohms

hence

10 ohm and 15 ohm are in parllel therefore

effective resistance = 15*10/(25) = 6 ohms

V= IR

I = 24/6 = 4A

current through 6ohm and 4 ohm is 24/10 = 2.4 A

current through 10 ohm and 5 ohm is 24/15 = 1.6 A

voltage across 6 ohm = 6*2.4 = 14.4 V

voltage across 4 ohm = 4* 2.4 = 9.6 V

voltage across 10 ohms = 10*1.6 = 16 V

voltage across 5 ohms = 5*1.6 = 8V