Question

According to a survey, 16% of U.S. adults with online services currently read e-books. Assume that this percentage is true for the current population of U.S. adults with online services. Find to 4 decimal places the probability that in a random sample of 600 U.S. adults with online services, the number who read e-books is

a. exactly 86.

Probability = Entry field with correct answer

b. at most 119.

Probability = Entry field with correct answer

c. 71 to 97.

Probability =

Answer 1

Solution:-

Given that

According to a survey, 16% of U.S. adults with online services currently read e-books. Assume that this percentage is true for the current population of U.S. adults with online services.

Find to 4 decimal places the probability that in a random sample of 600 U.S. adults with online services, the number who read e-books is

Given

This probabilities are solved by using R

Output :

Summary:

Given
n = 600 , p = 0.16
This can be solved by using binomial distribution .
1) exactly 86
Answer : P = 0.0000

2) at most 119 i.e. P( x 119)
Answer : P = 0.9946

3) between 71 to 97 that is

P( 71 < X < 97) = P( X 96) - p(X 71)
Answer : P= 0.5248

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