Question
In: Statistics and Probability
In a survey of 2580 adults, 1416 say they have started paying bills online in the...
In a survey of 2580 adults, 1416 say they have started paying bills online in the last year.
Construct a 99% confidence interval for the population proportion. Interpret the results.
A 99% confidence interval for the population proportion is ( _, _ ) (Round to three decimal places as needed.)
Interpret your results. Choose the correct answer below.
A. The endpoints of the given confidence interval show that adults pay bills online 99% of the time.
B. With 99% confidence, it can be said that the sample proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval.
C. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval.
Solutions
Expert Solution
n = 2580
p = 1416 / 2580 = 0.549
Z for 99% confidence interval = Z0.005 = 2.575
Confidence interval 
= (0.524 , 0.574)
Option-C) With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval
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