Question

In: Statistics and Probability

The director of library services at a college did a survey of types of books (by...

The director of library services at a college did a survey of types of books (by subject) in the circulation library. Then she used library records to take a random sample of 888 books checked out last term and classified the books in the sample by subject. The results are shown below.

Subject Area Percent of Books on Subject in Circulation
Library on This Subject
Number of Books in
Sample on This Subject
Business 32% 259
Humanities 25% 228
Natural Science 20% 221
Social Science 15% 101
All other subjects 8% 79

Using a 5% level of significance, test the claim that the subject distribution of books in the library fits the distribution of books checked out by students.

(a) What is the level of significance?


State the null and alternate hypotheses.

H0: The distributions are the same.
H1: The distributions are different.H0: The distributions are different.
H1: The distributions are different.    H0: The distributions are the same.
H1: The distributions are the same.H0: The distributions are different.
H1: The distributions are the same.


(b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to three decimal places. Round the test statistic to three decimal places.)


Are all the expected frequencies greater than 5?

YesNo    


What sampling distribution will you use?

chi-squareuniform    normalbinomialStudent's t


What are the degrees of freedom?


(c) Estimate the P-value of the sample test statistic.

P-value > 0.1000.050 < P-value < 0.100    0.025 < P-value < 0.0500.010 < P-value < 0.0250.005 < P-value < 0.010P-value < 0.005


(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis of independence?

Since the P-value > ?, we fail to reject the null hypothesis.Since the P-value > ?, we reject the null hypothesis.    Since the P-value ? ?, we reject the null hypothesis.Since the P-value ? ?, we fail to reject the null hypothesis.


(e) Interpret your conclusion in the context of the application.

At the 5% level of significance, the evidence is sufficient to conclude that the subject distribution of books in the library is different from that of books checked out by students.At the 5% level of significance, the evidence is insufficient to conclude that the subject distribution of books in the library is different from that of books checked out by students.

Solutions

Expert Solution

a) Level of Significance

State the null and alternate hypotheses.

H0: The distributions are the same.
H1: The distributions are different.

b) The Expected frequencies and chi square test statistic are given below

Subject Area Percent of Books on Subject in Circulation Number of Books in
Library on This Subject (p) Sample on This Subject (O) Exp. Freq.     E = np (O-E)^2/E
Business 32% 259 284.16 2.228
Humanities 25% 228 222 0.162
Natural Science 20% 221 177.6 10.606
Social Science 15% 101 133.2 7.784
All other subjects 8% 79 71.04 0.892
Total 888 888 21.671

Are all the expected frequencies greater than 5?

Answer: Yes

What sampling distribution will you use?

Answer: chi-square

What are the degrees of freedom?

Answer: degrres if freedom = n-1= 5-1=4

Under H0, the test statistic is

c) The P-Value is 0.000233

The p value < 0.005

d) Since the P-value ? ?, we reject the null hypothesis.Since the P-value ? ?, we fail to reject the null hypothesis.

e) At the 5% level of significance, the evidence is sufficient to conclude that the subject distribution of books in the library is different from that of books checked out by students.


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