Question

in C

i have a 2d array char m[8][8] =

{{1,1,1,1,1,1,1,1},
{1,0,0,0,1,0,0,1},
{1,0,1,0,1,1,0,1},
{1,0,1,0,0,0,0,1},
{1,0,1,1,1,1,0,1},
{1,0,0,0,0,0,0,1},
{1,0,1,0,1,0,1,1},
{1,1,1,1,1,1,1,1}}

turn this array into a 8 integer array int new[8]={-1,-119,-83, ......}

i.e Two's Complement to integer 10001001 --> -119

Answer 1

Please find the answer below.
Please do comments in case of any issue. Also, don't forget to rate the question. Thank You So Much.

#include <stdio.h>

int getConvertedToDecimal(int * a, int size){
   int val=0;
   int i;
   int twoVal=1;
   for(i=7;i>=0;i--){
       val += twoVal*a[i];
       twoVal= twoVal*2;
   }
   return val-256;
}

int main()
{
   int array[8][8] = {{1,1,1,1,1,1,1,1},
           {1,0,0,0,1,0,0,1},
           {1,0,1,0,1,1,0,1},
           {1,0,1,0,0,0,0,1},
           {1,0,1,1,1,1,0,1},
           {1,0,0,0,0,0,0,1},
           {1,0,1,0,1,0,1,1},
           {1,1,1,1,1,1,1,1}};
   int size=8;
   int i;

   int newArray[8];
   for(i=0;i<8;i++){
       int dec=getConvertedToDecimal(array[i],size);
       newArray[i] = dec;
   }

   printf("The content of array is : ");
   for(i=0;i<8;i++){
       printf("%d ",newArray[i]);
   }
   return 0;
}