A particle of charge q and mass m is accelerated from rest through a potential difference...

A particle of charge q and mass m is accelerated from rest through a potential difference V, after which it encounters a uniform magnetic field B perpendicular to its velocity v. If the particle moves in a plane perpendicular to B,

(a) Find an expression for the radius of its circular path in terms of q, V and B.

(b) If the particle is an electron, what must the potential difference be so it describes a circular path of radius 1.5 m in a magnetic field of 0.05 T?

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Expert Solution

genius_generous answered 1 year ago

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