A deuteron (charge +e, mass 2mp) is accelerated through 2.75 kV from rest and attains a...

A deuteron (charge +e, mass 2mp) is accelerated through 2.75 kV from rest and attains a final velocity in the j direction. It then enters a uniform magnetic field B= 1.64 Tk (note T = tesla)

a) Determine the magnitude of the final velocity attained by the deuteron after being accelerated through the 2.75 kV potential.

B) Determine the magnitude and direction of the magnetic force that the deuteron experiences just at the point of entering the uniform magnetic field? Express this result in vector notation.

C) Determine the Value of the acceleration of the deuteron when it enters the magnetic field.

D) Having entered the uniform magnetic field, the deuteron's path will be that of a circular arc. Determine the value of the radius of this arc.

E) From the discussion above, state explicitly how the acceleration you found in part (d) changes the velocity of the deuteron.

Solutions

Expert Solution

genius_generous answered 1 year ago

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