Question

Complete the following reaction. Add hydrogen atoms and charges to the appropriate atoms.

Answer 1

Concepts and reason

The problem is based on the concept of calculation of the hydrolysis of the amide group. Hydrolysis of amide group takes place differently in acidic and basic medium.

Fundamentals

Hydrolysis of the amide group in acidic medium results in the formation of carboxylic acid and ammonium salt. Hydrolysis of the amide group in basic medium results in the formation of carboxylate ion and an amine.

 

Part a

The following reaction takes place when N-methylpropanamide reacts with water in a basic medium (presence of NaOH)

The products of hydrolysis of N-methylpropanamide in the basic medium are shown as follows:

Hydrolysis of an alkanamide leads to the formation of a carboxylic acidic and an amine. In the basic medium, the carboxylic acid is converted to carboxylate ion and in the acidic medium, the amine group is converted to ammonium ion.

 

Part b

The following reaction takes place when N-methylpropanamide reacts with water in an acidic medium (presence of HCl)

The products of hydrolysis of N-methylpropanamide are in acidic medium shown follows:

Hydrolysis of an alkanamide leads to the formation of a carboxylic acidic and an amine. In the basic medium, the carboxylic acid is converted to carboxylate ion and in the acidic medium, the amine group is converted to ammonium ion.

 

Part a

The products of hydrolysis of N-methylpropanamide in basic medium are shown follows:

Part b

The products of hydrolysis of N-methylpropanamide are in acidic medium shown follows: